Find the value of m so that the quadratic equation mx (5x - 6) + 9 = 0 has two equal roots

[Term 2] Find value of 𝑚 so that quadratic equation 𝑚𝑥(5𝑥 − 6) = 0 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [Term 2]

part 2 - Question 2 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [Term 2] - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 2 Find the value of 𝑚 so that the quadratic equation 𝑚𝑥(5𝑥 − 6) + 9 = 0 has two equal roots. Given equation 𝑚𝑥(5𝑥 − 6) + 9 = 0 5𝑚𝑥2 − 6𝑚𝑥 + 9 = 0 Comparing equation with ax2 + bx + c = 0 a = 5𝑚, b = –6𝑚, c = 9 Since the equation has 2 equal roots, D = 0 b2 – 4ac = 0 Putting values (–6𝑚)2 – 4 × 5𝑚 × 9 = 0 36𝑚2 – 180𝑚 = 0 6(6𝑚2 – 30𝑚) = 0 6𝑚2 – 30𝑚 = 0 6(𝑚2 – 5𝑚) = 0 𝑚2 – 5𝑚 = 0 𝑚(𝑚 − 5) = 0 Thus, 𝑚 = 0 and 𝑚 = 5 But, if 𝑚 = 0, then the equation would not be a quadratic equation So, 𝑚 = 0 is not possible ∴ Correct answer is 𝑚 = 5

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo