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Ex 3.6, 1 - Chapter 3 Class 6 Playing with Numbers - Part 8

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Ex 3.6, 1 Find the HCF of the following numbers : (h) 91, 112, 49 HCF of 91, 112, 49 91 = 7 × 13 112 = 2 × 2 × 2 × 2 × 7 49 = 7 × 7 HCF of 91, 112, 49 = 7

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.