Example 11 - A wall of length 10 m was to be built across - Volume Of Cube/Cuboid

Example 11 - Chapter 13 Class 9 Surface Areas and Volumes - Part 2
Example 11 - Chapter 13 Class 9 Surface Areas and Volumes - Part 3


Transcript

Question 4 A wall of length 10 m was to be built across an open ground. The height of the wall is 4 m and thickness of the wall is 24 cm. If this wall is to be built up with bricks whose dimensions are 24 cm × 12 cm × 8 cm, how many bricks would be required? Total number of bricks = (𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝑤𝑎𝑙𝑙)/(𝑣𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝑏𝑟𝑖𝑐𝑘𝑠) Hence we need to find volume of wall & volume of bricks For wall Length of wall = 10m Breadth of wall = 24 cm Height of wall = 4 m Volume of the wall = Length × Breadth × height = 1000 × 24 × 400 cm3 For brick Length of brick = 24 cm Breadth of brick = 12 cm Height of brick = 8 cm volume of each brick = length × breadth × height = 24 × 12 × 8 cm3 Now, Total number of bricks = (𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝑤𝑎𝑙𝑙)/(𝑣𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝑏𝑟𝑖𝑐𝑘𝑠) = (1000 × 24 × 400)/(24 × 12 × 8) = 4166.6 = 4167(approx.) So, the wall requires 4167 (approx.) bricks.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.