Ex 11.3, 2 (i) - Chapter 11 Class 9 Surface Areas and Volumes

Last updated at July 22, 2026 by

Ex 11.3, 2 (i) Class 9 - Find capacity in litres of a conical vessel - Ex 11.3

part 2 - Ex 11.3, 2 (i) - Ex 11.3 - Serial order wise - Chapter 11 Class 9 Surface Areas and Volumes

 

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Ex 11.3, 2 Find the capacity in litres of a conical vessel with radius 7 cm, slant height 25 cm Given Radius of cone = r = 7 cm Slant height = l = 25 cm Let height of cone = h cm We know that l2 = h2 + r2 252 = h2 + 72 252 – 72 = h2 h2 = 252 – 72 h2 = (25 – 7) (25 + 7) h2 = (18) (32) h = √("18(32)" ) h = √("(9 × 2) × (32)" ) h = √("(9) × (64)" ) h = √("(32) × (82)" ) h = 3 × 8 h = 24 cm Capacity = Volume of cone = 1/3πr2h = 1/3 × 22/7 × 7 × 7 × 24 cm3 = 22 × 1 × 7 × 8 cm3 = 1232 cm3. = 1232 × 1/1000 litres = 1.232 litres

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