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The probability that a non leap year selected at random will contain 53 Sundays is

(A) 1/7Β  (B) 2/7

(C) 3/7Β  Β  (D) 5/7

Β 

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Question 11 The probability that a non leap year selected at random will contain 53 Sundays is (A) 1/7 (B) 2/7 (C) 3/7 (D) 5/7 A non leap year has 365 days Dividing by 7 Number of weeks in non-leap year = 365/7 = πŸ“πŸ 𝟏/πŸ• Thus, a non-leap year has 52 weeks, and 1 day extra That 1 extra day can be {Mon, Tues, Wed, Thur, Fri, Sat, Sun} Thus, Probability that a non leap year will contain 53 Sundays = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘†π‘’π‘›π‘‘π‘Žπ‘¦ 𝑖𝑛 π‘Ž π‘€π‘’π‘’π‘˜)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘›π‘’π‘Ÿ π‘œπ‘“ π‘‘π‘Žπ‘¦π‘  𝑖𝑛 π‘Ž π‘€π‘’π‘’π‘˜) = 𝟏/πŸ• So, the correct answer is (A)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.