The probability that a non leap year selected at random will contain 53 Sundays is
(A) 1/7Β (B) 2/7
(C) 3/7Β Β (D) 5/7
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Last updated at Oct. 27, 2021 by Teachoo
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Question 11 The probability that a non leap year selected at random will contain 53 Sundays is (A) 1/7 (B) 2/7 (C) 3/7 (D) 5/7 A non leap year has 365 days Dividing by 7 Number of weeks in non-leap year = 365/7 = ππ π/π Thus, a non-leap year has 52 weeks, and 1 day extra That 1 extra day can be {Mon, Tues, Wed, Thur, Fri, Sat, Sun} Thus, Probability that a non leap year will contain 53 Sundays = (ππ’ππππ ππ ππ’ππππ¦ ππ π π€πππ)/(πππ‘ππ ππ’ππππ ππ πππ¦π ππ π π€πππ) = π/π So, the correct answer is (A)