The probability that a non leap year selected at random will contain 53 Sundays is

(A) 1/7  (B) 2/7

(C) 3/7    (D) 5/7

 

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  1. Chapter 15 Class 10 Probability (Term 1)
  2. Serial order wise

Transcript

Question 11 The probability that a non leap year selected at random will contain 53 Sundays is (A) 1/7 (B) 2/7 (C) 3/7 (D) 5/7 A non leap year has 365 days Dividing by 7 Number of weeks in non-leap year = 365/7 = ๐Ÿ“๐Ÿ ๐Ÿ/๐Ÿ• Thus, a non-leap year has 52 weeks, and 1 day extra That 1 extra day can be {Mon, Tues, Wed, Thur, Fri, Sat, Sun} Thus, Probability that a non leap year will contain 53 Sundays = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘†๐‘ข๐‘›๐‘‘๐‘Ž๐‘ฆ ๐‘–๐‘› ๐‘Ž ๐‘ค๐‘’๐‘’๐‘˜)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘›๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘‘๐‘Ž๐‘ฆ๐‘  ๐‘–๐‘› ๐‘Ž ๐‘ค๐‘’๐‘’๐‘˜) = ๐Ÿ/๐Ÿ• So, the correct answer is (A)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.