Ex 13.6, 2
The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm3 of wood has a mass of 0.6 g.
To find mass,
we have to find volume of pipe
Volume of pipe = Volume of outer cylinder β Volume of inner cylinder
Outer cylinder
Radius of outer cylinder = r1 = (π·πππππ‘ππ ππ ππ’π‘ππ ππ¦ππππππ)/2 = 28/2 = 14 cm
Height of outer cylinder = h = 35 cm
Volume of outer cylinder = ππ12β
= π(14)2(35)
Inner Cylinder
Radius of inner cylinder = (π·πππππ‘ππ ππ πππππ ππ¦ππππππ)/2 = r2 = 24/2 = 12 cm
Height of inner cylinder = h = 35 cm
Volume of inner cylinder = ππ22β
= π(12)2(35)
Now,
Volume of pipe = Volume of outer cylinder β Volume of inner
Volume of pipe = π(14)2(35) β π(12)2(35)
= π(35)( (14)2β(12)2)
= 22/7Γ(35)Γ( 14 β12)(14+12)
= 22 Γ 5 Γ 2 Γ 26
= 5720 cm3
Now it is given that
Mass of 1 cm3 volume = 0.6 g
β΄ Mass of 5720 cm3 volume = (5720 Γ 0.6) g
= ((5720Γ0.6)/1000) kg
= 3.432 kg.
Therefore, mass of pipe is 3.432 kg

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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