Ex 11.1, 8 - Chapter 11 Class 9 Surface Areas and Volumes

Last updated at April 16, 2024 by Teachoo

Transcript

Ex 11.1,8
A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is Rs 12 per m2, what will be the cost of painting all these cones? (Use π = 3.14 and take √("1.04" ) = 1.02)
Curved surface area of cone will be painted
Curved surface area of 1 cone = πrl
Given Height = h = 1m
Radius = r = 40/2 = 20 cm = 1/100 × 20 m = 0.2 m
Let slant height be l
l2 = h2 + r2
l2 = "(1)2 + (0.2)2"
l2 = 1+0.04
l = √1.04
l = 1.02 m
Curved surface area of 1 cone = πr l
= 3.14 × 0.2 × 1.02 m2
= 0.64046 m2
Curved Surface Area of 50 cones = 50 × 0.64046
= 32.028 m2
Cost of painting 1 m2 = Rs 12
Cost of painting 32.028 m2 = Rs 12 × 32.028
= Rs 384.336
= Rs 384.34 (approx.)
So, Cost of painting 50 cones is Rs 384.34

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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