the pic is not clear
if your qstn is sm as this
AB is a diameter of a circle with centre O and AT is a tangent. If angle AOQ=58 find angle ATQ.
answer is
Angle ABQ=1/2 angle AOQ
=1/2*58
=29
Angle A =90(AT is a tangent)
angle BAT+angle ABT +angle ATQ=180(angle sum
property of triangle.)
90+29+angle ATQ= 180
angle ATQ=180-119
angle ATQ=61
Written on Dec. 6, 2017, 10:36 p.m.