We know that the sum of the interior angles of a triangle is. Let the third angle in all the given triangles be. Therefore, (i)38∘+100∘+x∘=180∘ x∘=180∘−138∘ x∘=42∘ Check from here

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We know that the sum of the interior angles of a triangle is. Let the third angle in all the given triangles be. Therefore,

(i) $3 8^{\circ} + 10 0^{\circ} + x^{\circ} = 18 0^{\circ}$

$x^{\circ} = 18 0^{\circ} - 13 8^{\circ}$

$x^{\circ} = 4 2^{\circ}$

Check from here

Written on Nov. 2, 2020, 11:31 a.m.

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