Answers!
From the first equation, \(x+y=5\), \(y\) is expressed as \(y=5-x\)
.
The expression for \(y\) is substituted into the second equation: \(2x-3(5-x)=4\).
The equation is simplified: \(2x-15+3x=4\), which leads to \(5x-15=4\).
The value of \(x\) is found by solving \(5x=19\), resulting in \(x=\frac{19}{5}\).
The value of \(x\) is substituted back into \(y=5-x\), yielding \(y=5-\frac{19}{5}\).
The value of \(y\) is calculated as \(y=\frac{25}{5}-\frac{19}{5}=\frac{6}{5}\). Final Answer
The solution is \(x=\frac{19}{5}\) and \(y=\frac{6}{5}\)
Comment
X+y=5 2x - 3y = with solution
Answer the question...
From the first equation, \(x+y=5\), \(y\) is expressed as \(y=5-x\)
.
The expression for \(y\) is substituted into the second equation: \(2x-3(5-x)=4\).
The equation is simplified: \(2x-15+3x=4\), which leads to \(5x-15=4\).
The value of \(x\) is found by solving \(5x=19\), resulting in \(x=\frac{19}{5}\).
The value of \(x\) is substituted back into \(y=5-x\), yielding \(y=5-\frac{19}{5}\).
The value of \(y\) is calculated as \(y=\frac{25}{5}-\frac{19}{5}=\frac{6}{5}\). Final Answer
The solution is \(x=\frac{19}{5}\) and \(y=\frac{6}{5}\)
.
The expression for \(y\) is substituted into the second equation: \(2x-3(5-x)=4\).
The equation is simplified: \(2x-15+3x=4\), which leads to \(5x-15=4\).
The value of \(x\) is found by solving \(5x=19\), resulting in \(x=\frac{19}{5}\).
The value of \(x\) is substituted back into \(y=5-x\), yielding \(y=5-\frac{19}{5}\).
The value of \(y\) is calculated as \(y=\frac{25}{5}-\frac{19}{5}=\frac{6}{5}\). Final Answer
The solution is \(x=\frac{19}{5}\) and \(y=\frac{6}{5}\)
Comment
X+y=5 2x - 3y = with solution