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Short Quiz - Chapter 6 Class 10 Triangles

Chapter 6 Class 10 Triangles | 5 questions

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Question 1 of 5
Question 1 of 5
NCERT Exemplar
If \(\triangle \mathrm{ABC} \sim \triangle \mathrm{QRP}, \frac{\operatorname{ar}(\mathrm{ABC})}{\operatorname{ar}(\mathrm{PQR})}=\frac{9}{4}, \mathrm{AB}=18 \mathrm{~cm}\) and \(\mathrm{BC}=15 \mathrm{~cm}\), then PR is equal to
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Question 2 of 5
Rohan wants to
Rohan wants to
Rohan wants to measure the distance of a pond during the visit to his native. He marks points A and B on the opposite edges of a pond as shown in the figure below. To find the distance between the points, he makes a right-angled triangle using rope connecting B with another point C are a distance of 12 m, connecting C to point D at a distance of 40 m from point C and the connecting D to the point A which is are a distance of 30 m from D such the A D C=900.
Which property of geometry will be used to find the distance AC?
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Question 3 of 5
NCERT Exemplar
If S is a point on side PQ of a \(\triangle \mathrm{PQR}\) such that \(\mathrm{PS}=\mathrm{QS}=\mathrm{RS}\), then
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Question 4 of 5
Vijay is trying
Vijay is trying
Vijay is trying to find the average height of a tower near his house. He is using the properties of similar triangles. The height of Vijay's house if 20 m when Vijay's house casts a shadow 10 m long on the ground. At the same time, the tower casts a shadow 50 m long on the ground and the house of Ajay casts 20 m shadow on the ground.
When the tower casts a shadow of 40 m , same time what will be the length of the shadow of Vijay's house?
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Question 5 of 5
NCERT Exemplar
It is given that \(\triangle \mathrm{ABC} \sim \triangle \mathrm{DFE}, \angle \mathrm{A}=30^{\circ}, \angle \mathrm{C}=50^{\circ}, \mathrm{AB}=5 \mathrm{~cm}, \mathrm{AC} =8 \mathrm{~cm}\) and \(\mathrm{DF}=7.5 \mathrm{~cm}\). Then, the following is true:
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