Teachoo MCQ Test

10 Question MCQ (including Assertion)

Preparing for CBSE

Chapter 6 Class 7 - Constructions and Tilings (Ganita Prakash II) | 10 questions

Timed test. Answer every question before time runs out. Correct answers and solutions appear after submission.
Time remaining 960
Question 1 of 10
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Question 1 of 10
Line \(AB\) is the perpendicular bisector of \(XY\) and meets it at \(O\). If \(XY=14\) cm, what is \(OY\)?
Perpendicular-bisector constructionSegment XY with equal-distance points A and B joined through O.XYABO
Select one option. Answers are shown after the test.
Question 2 of 10
Which calculation gives a \(15°\) angle using the chapter’s \(60°\) construction and bisection?
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Question 3 of 10
An arc of radius 7 cm from X and an arc of radius 9 cm from Y meet at P. Why is P not guaranteed to lie on the perpendicular bisector of XY?
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Question 4 of 10
Assertion (A): A region with 9 black and 7 white squares can be tiled by 8 dominoes.
Reason (R): Eight dominoes would cover 16 squares.
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Question 5 of 10
In the diagram, \(AX=AY\), \(BX=BY\), and AB meets XY at O. Which proof chain establishes that AB is the perpendicular bisector of XY?
Perpendicular-bisector constructionSegment XY with equal-distance points A and B joined through O.XYABO
Select one option. Answers are shown after the test.
Question 6 of 10
Assertion (A): The angle-copy construction preserves the original angle.
Reason (R): The two construction triangles have equal arc-radius sides and an equal transferred chord, so they are congruent by SSS.
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Question 7 of 10
On a line, points X and Y are marked so that \(OX=OY\). A point A satisfies \(AX=AY\). What is \(∠AOY\)?
Constructing a perpendicular at OO is marked as the midpoint of XY and A is equidistant from X and Y.XOYA
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Question 8 of 10
On a checkerboard-coloured grid, what does every \(2\times1\) domino cover?
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Question 9 of 10
A right angle is bisected, and one resulting angle is bisected again. What is the smallest angle formed?
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Question 10 of 10
Assertion (A): Six \(60°\) equilateral-triangle angles meet exactly at the centre of a regular hexagon.
Reason (R): \(6\times60°=360°\).
Regular hexagonA regular hexagon centred at O; the answer divides it into six equilateral triangles.O3 cmABCDEF
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