Ex 9.2, 11 - Chapter 9 Class 7 Perimeter and Area
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 9.2, 11 A circle of radius 2 cm is cut out from a square piece of an aluminum sheet of side 6 cm. What is the area of the left over aluminum sheet? (Take π = 3.14) Let ABCD be the square sheet of side 6 cm Remaining Area = Area of square sheet − Area of circular piece Area of square sheet Side of sheet = a = 6 cm Area of square sheet = a × a = 6 × 6 = 36 cm2 Area of circular Radius of circular = r = 2 cm Area of circular = 𝜋r2 = 3.14 × (2)2 = 314/100 × 4 = 1256/100 = 12.56 cm2 Now, Remaining Area = Area of square sheet − Area of circular piece = 36 − 12.56 = 36 − 1256/100 = (36 × 100 − 1256)/100 = (𝟑𝟔𝟎𝟎 − 𝟏𝟐𝟓𝟔)/𝟏𝟎𝟎 = 2344/100 = 23.44 cm2 ∴ 23.44 cm2 of area is left.
Ex 9.2
Ex 9.2, 1 (b) Important
Ex 9.2, 1 (c)
Ex 9.2, 2 (a) Important
Ex 9.2, 2 (b) Important
Ex 9.2, 2 (c)
Ex 9.2, 3
Ex 9.2, 4 Important
Ex 9.2, 5 Important
Ex 9.2, 6
Ex 9.2, 7 Important
Ex 9.2, 8
Ex 9.2, 9 Important
Ex 9.2, 10 Important
Ex 9.2, 11 You are here
Ex 9.2, 12 Important
Ex 9.2, 13 Important
Ex 9.2, 14
Ex 9.2, 15
Ex 9.2, 16 Important
Ex 9.2, 17 Important
About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo