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Ex 9.1, 3 Find the missing values: Base = 20 cm, Height = ?, Area = 246 cm2 Base = b = 20 cm Height = h Area of parallelogram = b ร— h 246 = 20 ร— h ๐Ÿ๐Ÿ’๐Ÿ”/๐Ÿ๐ŸŽ = h 123/10 = h 12.3 = h h = 12.3 cm โˆด Height = 12.3 cm (b) Base = ?, Height = 15 cm, Area = 154.5 cm2 Base = b Height = h = 15 cm Area of parallelogram = b ร— h 154.5 = b ร— 15 154.5/15 = b b = (๐Ÿ๐Ÿ“๐Ÿ’.๐Ÿ“)/๐Ÿ๐Ÿ“ b = 1545/15 ร— 1/10 b = ๐Ÿ‘๐ŸŽ๐Ÿ—/๐Ÿ‘ ร— ๐Ÿ/๐Ÿ๐ŸŽ b = 103 ร— 1/10 b = 10.3 cm โˆด Base = 10.3 cm (c) Base = ?, Height = 8.4 cm, Area = 48.72 cm2 Base = b Height = h = 8.4 cm Area of parallelogram = b ร— h 48.72 = b ร— 8.4 48.72/8.4 = b b = 48.72 ร— ๐Ÿ/(๐Ÿ–.๐Ÿ’) b = 4872/100 ร— 10/84 b = 4872/10 ร— 1/84 b = ๐Ÿ’๐Ÿ–๐Ÿ•๐Ÿ/๐Ÿ–๐Ÿ’ ร— ๐Ÿ/๐Ÿ๐ŸŽ b = 1281/21 ร— 1/10 b = 406/7 ร— 1/10 b = 58 ร— 1/10 b = 5.8 cm โˆด Base = 5.8 cm (d) Base = 15.6 cm, Height = ?, Area = 16.38 cm2 Base = b = 15.6 cm Height = h Area of parallelogram = b ร— h 16.38 = 15.6 h 16.38/15.6 = h h = (๐Ÿ๐Ÿ”.๐Ÿ‘๐Ÿ–)/(๐Ÿ๐Ÿ“.๐Ÿ”) h = 16.38 ร— 1/15.6 h = ๐Ÿ๐Ÿ”๐Ÿ‘๐Ÿ–/๐Ÿ๐ŸŽ๐ŸŽ ร— ๐Ÿ๐ŸŽ/๐Ÿ๐Ÿ“๐Ÿ” h = 1638/10 ร— 1/156 h = ๐Ÿ๐Ÿ”๐Ÿ‘๐Ÿ–/๐Ÿ๐Ÿ“๐Ÿ” ร— ๐Ÿ/๐Ÿ๐ŸŽ h = 819/78 ร— 1/10 h = 273/26 ร— 1/10 h = ๐Ÿ๐Ÿ/๐Ÿ ร— ๐Ÿ/๐Ÿ๐ŸŽ h = 10.5 ร— 1/10 h = 1.05 โˆด Height = 1.05 cm

  1. Chapter 9 Class 7 Perimeter and Area
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo