Ex 5.3, 9 - Chapter 5 Class 8 Squares and Square Roots
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 5.3, 9 Find the smallest square number that is divisible by each of the numbers 4, 9 and 10.Smallest square number divisible by 4, 9 and 10 = L.C.M of 4, 9 and 10 OR Multiple of L.C.M Finding L.C.M of 4, 9, 10 L.C.M of 4, 9, 10 = 2 × 2 × 3 × 3 × 5 = 4 × 9 × 5 = 180 Checking if 180 is a perfect square We see that 180 = 2 × 2 × 3 × 3 × 5 Since 5 is not in pair, ∴ 180 is not a perfect square. So, we multiply by 5 to make pairs So, our number becomes 180 × 5 = 2 × 2 × 3 × 3 × 5 × 5 900 = 2 × 2 × 3 × 3 × 5 × 5 Now, it becomes a perfect square. Thus, required number is 900
Ex 5.3
Ex 5.3, 1 (ii) Important
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Ex 5.3, 4 (ix)
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Ex 5.3, 10
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo