1. Chapter 13 Class 11 Statistics
  2. Serial order wise
  3. Ex 13.2
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Ex 13.2, 9 - Chapter 13 Class 11 Statistics

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Ex15.2, 9 Find the mean, variance and standard deviation using short-cut method Mean(π‘₯ Μ…) = A + (βˆ‘β–’π‘“π‘–π‘¦π‘–)/(βˆ‘β–’π‘“π‘–) Γ—β„Ž where A = assumed mean = 92.5 𝑦_𝑖=(π‘₯_𝑖 βˆ’ 𝐴)/β„Ž h = class size = 75 βˆ’ 70 = 5 Variance (𝜎)2 = β„Ž2/N2 [π‘βˆ‘β–’π‘“π‘–π‘¦π‘–2 βˆ’ (βˆ‘β–’π‘“π‘–π‘¦π‘–)^2 ] = 52/602 [N Γ— (254) – (6)2] = 25/3600 [60 Γ—254 βˆ’36] = 25/3600 Γ— 15204 = 105.58 ∴ Standard deviation (𝜎) = √Variance = √105.58 = 10.27
  1. Chapter 13 Class 11 Statistics
  2. Serial order wise

    3. Ex 13.2

    Examples →
Examples →
Chapter 13 Class 11 Statistics
Serial order wise

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo