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Transcript

Ex 13.1, 3 The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f. Mean(๐‘ฅ ฬ…) = a + (โˆ‘โ–’๐’‡๐’Š๐’…๐’Š)/(โˆ‘โ–’๐’‡๐’Š) Where a = Assumed Mean h = Class interval Putting values in formula Mean = 18 + (2๐‘“ โˆ’ 40)/(44 + ๐‘“) 18 = 18 + (2๐‘“ โˆ’ 40)/(44 + ๐‘“) 18 โˆ’ 18 = (2๐‘“ โˆ’ 40)/(44 + ๐‘“) 0 = (2๐‘“ โˆ’ 40)/(44 + ๐‘“) 0 = 2๐‘“โˆ’40 2๐‘“=40 f = 40/2 f = 20

  1. Chapter 13 Class 10 Statistics
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo