1. Chapter 12 Class 10 Surface Areas and Volumes
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  3. Frustum - Area and Volume
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Question 2 - Frustum - Area and Volume - Chapter 12 Class 10 Surface Areas and Volumes

Last updated at Dec. 13, 2024 by Teachoo

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Question 2 The slant height of a frustum of a cone is 4 cm and the perimeters (circumference) of its circular ends are 18 cm and 6 cm. Find the curved surface area of the frustum. We know that Curved surface area of frustum = ( 1+ 2) Here l = 4 cm We need to find r1 & r2 Now, Curved surface area of frustum = ( 1+ 2) = (9/ +3/ ) 4 = ((9 + 3)/ ) 4 = 12/ 4 = 48 cm2 Hence, curved surface area of frustum = 48 cm2
  1. Chapter 12 Class 10 Surface Areas and Volumes
  2. Serial order wise

    3. Frustum - Area and Volume

    Important Questions on Surface Area and Volume →
Important Questions on Surface Area and Volume →
Chapter 12 Class 10 Surface Areas and Volumes
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo