Last updated at Dec. 16, 2024 by Teachoo
Ex 11.3, 4 Express the number appearing in the following statements in standard form. (h) 60,230,000,000,000,000,000,000 molecules are contained in a drop of water weighing 1.8 gm 60,230,000,000,000,000,000,000 = 6023 × 〖10〗^19 = (6.023 × 103) × 〖10〗^19 = 6.023 × 〖10〗^3 × 〖10〗^19 = 6.023 × 〖10〗^(3 + 19) = 6.023 × 〖10〗^22 Answer is 6.023 × 〖𝟏𝟎〗^𝟐𝟐 molecules (Using am × an = am + n)
Ex 11.3
Ex 11.3, 2 (a)
Ex 11.3, 2 (b) Important
Ex 11.3, 2 (c)
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Ex 11.3, 3 (i)
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Ex 11.3, 3 (iv)
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Ex 11.3, 3 (vi)
Ex 11.3, 4 (a) Important
Ex 11.3, 4 (b)
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Ex 11.3, 4 (d)
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Ex 11.3, 4 (f)
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Ex 11.3, 4 (h) Important You are here
Ex 11.3, 4 (i)
Ex 11.3, 4 (j) Important
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo