Last updated at Dec. 13, 2024 by Teachoo
Question 5 In the given figure, if PQ ⊥ PS, PQ || SR, ∠SQR = 28° and ∠QRT = 65°, then find the values of x and y. Since PQ || SR and QR is a transversal. ∠PQR = ∠QRT x + 28° = 65° x = 65° − 28° x = 37° In ΔSPQ, ∠ SPQ + x + y = 180° 90° + 37° + y = 180° y = 180° − 127° y = 53° Thus, x = 37° and y = 53°
Important Questions on Lines, Angles, Triangles
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo