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Transcript

Question 2 In the given figure, ∠X = 62°, ∠XYZ = 54°. If YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively of ΔXYZ, find ∠OZY and ∠YOZ. Given, OY is the angle bisector of ∠XYZ So, ∠XYO = ∠OYZ = 1/2(∠XYZ ) ∠XYO = ∠OYZ = 1/2 (54°) ∠XYO = ∠OYZ = 27° Also, OZ is the angle bisector of ∠XZY So, ∠XZO = ∠OZY = 1/2(∠XZY ) In ΔXYZ, ∠ YXZ + ∠ XYZ + ∠ XZY = 180° 62° + 54° + ∠ XZY = 180° ∠ XZY = 180° − 116° ∠ XZY = 64° From (2) ∠XZO = ∠OZY = 1/2(∠XZY ) ∠XZO = ∠OZY = 1/2 × 64° ∠XZO = ∠OZY = 32° In Δ OYZ ∠ OYZ + ∠ OZY + ∠ YOZ = 180° 27° + 32° + ∠ YOZ = 180° 59° + ∠ YOZ = 180° 59° + ∠ YOZ = 180° ∠YOZ = 180° − 59° ∠YOZ = 121°

  1. Chapter 6 Class 9 Lines and Angles
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo