Last updated at Dec. 13, 2024 by Teachoo
Question 2 In the given figure, ∠X = 62°, ∠XYZ = 54°. If YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively of ΔXYZ, find ∠OZY and ∠YOZ. Given, OY is the angle bisector of ∠XYZ So, ∠XYO = ∠OYZ = 1/2(∠XYZ ) ∠XYO = ∠OYZ = 1/2 (54°) ∠XYO = ∠OYZ = 27° Also, OZ is the angle bisector of ∠XZY So, ∠XZO = ∠OZY = 1/2(∠XZY ) In ΔXYZ, ∠ YXZ + ∠ XYZ + ∠ XZY = 180° 62° + 54° + ∠ XZY = 180° ∠ XZY = 180° − 116° ∠ XZY = 64° From (2) ∠XZO = ∠OZY = 1/2(∠XZY ) ∠XZO = ∠OZY = 1/2 × 64° ∠XZO = ∠OZY = 32° In Δ OYZ ∠ OYZ + ∠ OZY + ∠ YOZ = 180° 27° + 32° + ∠ YOZ = 180° 59° + ∠ YOZ = 180° 59° + ∠ YOZ = 180° ∠YOZ = 180° − 59° ∠YOZ = 121°
Important Questions on Lines, Angles, Triangles
About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo