Last updated at Dec. 13, 2024 by Teachoo
Question 1 In the given figure, sides QP and RQ of ΔPQR are produced to points S and T respectively. If ∠SPR = 135° and ∠PQT = 110°, find ∠PRQ. Since TR is a line ∠ PQT + ∠ PQR = 180° 110° + ∠ PQR = 180° ∠ PQR = 180° – 110° ∠ PQR = 70° Since QS is a line ∠ SPR + ∠ QPR = 180° 135° + ∠ QPR = 180° ∠ QPR = 180° – 135° ∠ QPR = 45° In Δ PQR, ∠ QPR + ∠ PQR + ∠ PRQ = 180° 45° + 70° + ∠ PRQ = 180° 115° + ∠ PRQ = 180° ∠ PRQ = 180° – 115° ∠ PRQ = 65°
Important Questions on Lines, Angles, Triangles
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo