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Question 1 - Graph Question (Easy) - Teachoo Questions - Chapter 8 Class 9 - Motion

Last updated at Dec. 16, 2024 by Teachoo

Find Displacement and Acceleration in region OA and OB. Also tell the type of motion in both the regions. And find the total displacement

Marking point C in the graph

 

Motion in region OA = Uniformly accelerated

Motion in region OB = Uniformly retarded

 Total Displacement = Area of โˆ†ABO

 = Area of โˆ†OAC + Area of โˆ†ABC

 = 4m + 4m

 = 8m  

Transcript

Region OA Acceleration = Slope of OA = (๐‘ฆ_2 โˆ’ ๐‘ฆ_1)/(๐‘ฅ_2 โˆ’ ๐‘ฅ_1 ) = (4 โˆ’ 0)/(2 โˆ’ 0) = 4/2 = 2 m/s2 Displacement = Area under v โ€“ t graph = Area of โˆ†OAC = 1/2 ร— b ร— h = 1/2 ร— 2 ร— 4 = 4 m Region AB Acceleration = Slope of BA = (๐‘ฆ_2 โˆ’ ๐‘ฆ_1)/(๐‘ฅ_2 โˆ’ ๐‘ฅ_1 ) = (0 โˆ’ 4)/(0 โˆ’ 2) = (โˆ’4)/2 = โˆ’2 m/s2 Displacement = Area under v โ€“ t graph = Area of โˆ†ABC = 1/2 ร— b ร— h = 1/2 ร— 2 ร— 4 = 4 km
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CA Maninder Singh is a Chartered Accountant for the past 14 years and a teacher from the past 18 years. He teaches Science, Economics, Accounting and English at Teachoo