Let us try an ancient problem from Lilavati. At that time weights were - Figure it out - Page 176, 177

part 2 - Question 5 - Figure it out - Page 176, 177 - Chapter 7 Class 8 - Proportional Reasoning-1(Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
part 3 - Question 5 - Figure it out - Page 176, 177 - Chapter 7 Class 8 - Proportional Reasoning-1(Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

Remove Ads Share on WhatsApp

Transcript

Question 5 Let us try an ancient problem from Lilavati. At that time weights were measured in a unit named palas and niskas was a unit of money. “If 2 1/2 palas of saffron costs 3/7 niskas, O expert businessman! tell me quickly what quantity of saffron can be bought for 9 niskas?” First, we convert mixed fractions to fractions 𝟐 𝟏/𝟐 palas =2+1/2 palas =(2 × 2 + 1)/2 palas =(4 + 1)/2 palas =𝟓/𝟐 palas Now, we are given that From 𝟑/𝟕 niskas, we get saffron as = 𝟓/𝟐 palas From 𝟏 niskas, we get saffron as = 𝟓/𝟐 × 𝟕/𝟑 palas = 𝟑𝟓/𝟔 palas Now, we are asked how much quatity of Saffron we can buy for 9 niskas Thus, Saffron brought from 9 niskas = 9 × Saffron brought from 1 niskas = 9 × 35/6 =3 × 35/2 = 105/2 = 52.5 palas Thus, we can buy 𝟓𝟐.𝟓 palas (or 𝟓𝟐 𝟏/𝟐 palas) of saffron.

CA Maninder Singh's photo - Co-founder, Teachoo

Made by

CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 16 years. He also provides Accounts Tax GST Training in Delhi, Kerala and online.