Question 2 - Figure it out - Page 170-171 - Chapter 7 Class 8 - Proportional Reasoning-1(Ganita Prakash)

Transcript

Question 2 A mason is building a house in the shape shown in the diagram. He needs to construct both the outer walls and the inner wall that separates two rooms. To build a wall of 10-feet, he requires approximately 1450 bricks. How many bricks would he need to build the house? Assume all walls are of the same height and thickness. First, we calculate the Total Length of wall required And, then we find Number of bricks Total Length of wall required Thus, we require Total length = (12 + 9 + 9 + 12) + (15 + 12 + 15) + (9 + 6 + 9) = 42 + 42 + 24 = 108 ft Number of Bricks Required Given that To build a wall of 10-feet, he requires approximately 1450 bricks First we find number of bricks to build a wall of 1 feet Then, we multiply that by 108 to find Number of bricks needed for 108 ft Now, Number of bricks needed to build a wall of 10 ft = 1450 Number of bricks needed to build a wall of 1 ft = 1450/10 = 145 Thus, Number of bricks needed to build a wall of 108 ft = 145 × 108 = 15,660 Thus, the mason needs 15,660 bricks.