Here is a table showing the number of pencils and erasers sold in - Simplification of Algebraic Expressions

part 2 - Example 5 - Simplification of Algebraic Expressions - Chapter 4 Class 7 - Expressions using Letter-Numbers (Ganita Prakash) - Class 7 (Ganit Prakash)
part 3 - Example 5 - Simplification of Algebraic Expressions - Chapter 4 Class 7 - Expressions using Letter-Numbers (Ganita Prakash) - Class 7 (Ganit Prakash)
part 4 - Example 5 - Simplification of Algebraic Expressions - Chapter 4 Class 7 - Expressions using Letter-Numbers (Ganita Prakash) - Class 7 (Ganit Prakash)

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Example 5 Here is a table showing the number of pencils and erasers sold in a shop. The price per pencil is c, and the price per eraser is d. Find the total money earned by the shopkeeper during these three days.Given Price per pencil = c Price per eraser = d Now, we do it day by day Day 1 5 pencils and 4 erasers were sold Now, Cost of 5 pencils = 5 × c = 5c Cost of 4 erasers = 4 × d = 4d Thus, Amount earned on Day 1 = 5c + 4d Day 2 3 pencils and 6 erasers were sold Now, Cost of 3 pencils = 3 × c = 3c Cost of 6 erasers = 6 × d = 6d Thus, Amount earned on Day 2 = 3c + 6d Day 3 10 pencils and 1 eraser were sold Now, Cost of 10 pencils = 10 × c = 10c Cost of 1 eraser = 1 × d = d Thus, Amount earned on Day 3 = 10c + d Therefore, Total Amount earned during 3 days = Amount earned on Day 1 + Amount earned on Day 2 + Amount earned on Day 3 = (5c + 4d) + (3c + 6d) + (10c + d) Grouping c together, and grouping d together = (5c + 3c + 10c) + (4d + 6d + d) = 18c + 11d

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo