Ex 11.2, 4 - Chapter 11 Class 9 Surface Areas and Volumes

Last updated at August 5, 2026 by

Ex 11.2, 4 - The radius of a spherical balloon increases - Ex 11.2

part 2 - Ex 11.2, 4 - Ex 11.2 - Serial order wise - Chapter 11 Class 9 Surface Areas and Volumes

 

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Ex 11.2 , 4 The radius of a spherical balloon increases from 7 cm to 14 cm as air is being pumped into it. Find the ratio of surface areas of the balloon in the two cases. Let r1 be the radius of smaller balloon = 7 cm and r2 be the radius of larger balloon = 14 cm Surface Area of sphere = 4 r2 Ratio of their surface areas = ( )/( ) = 4 12/4 22 = 12/ 22 = 7^2/ 14 ^2 = (7 7)/(14 14) = 1/4 Thus , the required ratio of their surface areas = 1 : 4

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