Last updated at Dec. 16, 2024 by Teachoo
Ex 8.4, 3 Simplify. (vi) (๐ฅ+๐ฆ)(๐ฅ^2โ๐ฅ๐ฆ+๐ฆ^2 ) (๐ฅ+๐ฆ)(๐ฅ^2โ๐ฅ๐ฆ+๐ฆ^2 ) = ๐ฅ(๐ฅ^2โ๐ฅ๐ฆ+๐ฆ^2 )+๐ฆ(๐ฅ^2โ๐ฅ๐ฆ+๐ฆ^2 ) = (๐ร๐^๐ )โ(๐ร๐๐)+(๐ร๐^๐ )+(๐ร๐^๐ )โ(๐ร๐๐)+(๐ร๐^๐ ) = ๐ฅ^3โ๐ฅ^2 ๐ฆ+๐ฅ๐ฆ^2+๐ฆ๐ฅ^2โ๐ฅ๐ฆ^2+๐ฆ^3 = ๐ฅ^3โ๐ฅ^2 ๐ฆ+๐ฅ^2 ๐ฆ+๐ฅ๐ฆ^2โ๐ฅ๐ฆ^2+๐ฆ^3 = ๐ฅ^3โ๐ฅ^2 ๐ฆ+๐ฅ^2 ๐ฆ+๐ฆ^3 = ๐^๐+๐^๐
Ex 8.4
Ex 8.4, 1 (ii)
Ex 8.4, 1 (iii) Important
Ex 8.4, 1 (iv)
Ex 8.4, 1 (v) Important
Ex 8.4, 1 (vi) Important
Ex 8.4, 2 (i)
Ex 8.4, 2 (ii) Important
Ex 8.4, 2 (iii)
Ex 8.4, 2 (iv) Important
Ex 8.4, 3 (i)
Ex 8.4, 3 (ii)
Ex 8.4, 3 (iii) Important
Ex 8.4, 3 (iv)
Ex 8.4, 3 (v) Important
Ex 8.4, 3 (vi) You are here
Ex 8.4, 3 (vii) Important
Ex 8.4, 3 (viii)
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo