Last updated at Dec. 16, 2024 by Teachoo
Ex 8.4, 1 Multiply the binomials. (v) (2๐๐ + 3๐^2 ) and (3๐๐ โ 2๐^2 ) (2๐๐ + 3๐^2 )(3๐๐ โ 2๐^2 ) = 2๐๐(3๐๐โ2๐^2 )+3๐^2 (3๐๐โ2๐^2 ) = (๐๐๐ ร ๐๐๐)โ(๐๐๐ ร ๐๐^๐ )+(๐๐^๐ ร ๐๐๐)โ(๐๐^๐ ร ๐๐^๐ ) = 6๐^2 ๐^2โ4๐๐^3+9๐๐^3โ6๐^4 = ๐๐^๐ ๐^๐+๐๐๐^๐โ๐๐^๐
Ex 8.4
Ex 8.4, 1 (ii)
Ex 8.4, 1 (iii) Important
Ex 8.4, 1 (iv)
Ex 8.4, 1 (v) Important You are here
Ex 8.4, 1 (vi) Important
Ex 8.4, 2 (i)
Ex 8.4, 2 (ii) Important
Ex 8.4, 2 (iii)
Ex 8.4, 2 (iv) Important
Ex 8.4, 3 (i)
Ex 8.4, 3 (ii)
Ex 8.4, 3 (iii) Important
Ex 8.4, 3 (iv)
Ex 8.4, 3 (v) Important
Ex 8.4, 3 (vi)
Ex 8.4, 3 (vii) Important
Ex 8.4, 3 (viii)
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo