Last updated at Dec. 16, 2024 by Teachoo
Ex 8.4, 1 Multiply the binomials. (i) (2๐ฅ + 5) and (4๐ฅ โ 3) (2๐ฅ+5) (4๐ฅโ3) = 2๐ฅ(4๐ฅโ3)+5(4๐ฅโ3) = (๐๐ ร ๐๐)โ(๐๐ ร ๐)+(๐ ร ๐๐)โ(๐ ร ๐) = 8๐ฅ^2โ6๐ฅ+20๐ฅโ15 = ๐๐^๐+๐๐๐โ๐๐
Ex 8.4
Ex 8.4, 1 (ii)
Ex 8.4, 1 (iii) Important
Ex 8.4, 1 (iv)
Ex 8.4, 1 (v) Important
Ex 8.4, 1 (vi) Important
Ex 8.4, 2 (i)
Ex 8.4, 2 (ii) Important
Ex 8.4, 2 (iii)
Ex 8.4, 2 (iv) Important
Ex 8.4, 3 (i)
Ex 8.4, 3 (ii)
Ex 8.4, 3 (iii) Important
Ex 8.4, 3 (iv)
Ex 8.4, 3 (v) Important
Ex 8.4, 3 (vi)
Ex 8.4, 3 (vii) Important
Ex 8.4, 3 (viii)
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo