Last updated at Dec. 16, 2024 by Teachoo
Misc, 5 A rod of length 12 cm moves with its ends always touching the coordinate axes. Determine the equation of the locus of a point P on the rod, which is 3 cm from the end in contact with the x-axis. Let AB be the rod where A touches the x-axis & B touches the y-axis Let point P(x, y) Given AB = Length of rod = 12 cm & AP = 3 cm PB = AB – AP PB = 12 – 3 = 9cm Drawing PQ ⊥ BO and PR ⊥ OA Hence, PQ = x & PR = y Let ∠ PAR = θ Now, PQ & AO are parallel lines (As both are perpendicular to y-axis) & BA is the transversal So ∠ BPQ = ∠ PAR = θ Now we know that, sin2𝜃 + cos2𝜃 = 1 Putting 𝑠𝑖𝑛𝜃 = 𝑦6 and 𝑐𝑜𝑠𝜃 = 𝑥9 𝑦32 + 𝑥92 = 1 𝑦29 + 𝑥281 = 1 𝒙𝟐𝟖𝟏 + 𝒚𝟐𝟗 = 1 Hence it satisfies the equation of ellipse 𝑥2𝑎2 + 𝑦2𝑏2 = 1 Thus locus of P is ellipse
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo