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Question 19 - Chemistry CBSE Class 12 Sample Paper for 2023 Boards - Solutions - Solutions to CBSE Sample Paper - Chemistry Class 12

Last updated at Dec. 13, 2024 by Teachoo

A first-order reaction takes 69.3 min for 50% completion. What is the time needed for 80% of the reaction to get completed?

(Given: log 5 =0.6990, log 8 = 0.9030, log 2 = 0.3010)

 

Answer:

Half life t1/2 = 0.693 /k

k= 0.693/69.3 = 1/100 = 0.01 min -1

For first order reaction

π‘˜ = 2.303/𝑑 π‘™π‘œπ‘” [π‘…π‘œ]/[𝑅]

𝑑 = 2.303/0.01 π‘™π‘œπ‘” 100/20

𝑑 = 230.3 log 5 (log 5 =0.6990)

t= 160.9 min

  1. Chemistry Class 12
  2. Solutions to CBSE Sample Paper - Chemistry Class 12

    3. Chemistry CBSE Class 12 Sample Paper for 2023 Boards - Solutions

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Solutions to CBSE Sample Paper - Chemistry Class 12

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo