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Example 1 (Method 1) Find the area of the sector of a circle with radius 4 cm and of angle 30°. Also, find the area of the corresponding major sector (Use π = 3.14). Given Radius = r = 4 cm, θ=30° Now, Area of sector = 𝜽/𝟑𝟔𝟎 × 𝝅𝒓𝟐 = 30/360 × 3.14 × (4)2 = 𝟏/𝟏𝟐 × 𝟑.𝟏𝟒 × 𝟒 × 𝟒 = 1/3 × 3.14 × 4 = 12.56/3 cm2 = 4.19 cm2 Area of major sector = ((𝟑𝟔𝟎 − 𝛉))/𝟑𝟔𝟎×𝝅𝒓𝟐 = ((360 − 30))/360 × 3.14 × (4)2 = 𝟑𝟑𝟎/𝟑𝟔𝟎 × 𝟑.𝟏𝟒 × 𝟒 × 𝟒 = 11/12 × 3.14 × 4 × 4 = 46.05 cm2 Example 1 (Method 2) Find the area of the sector of a circle with radius 4 cm and of angle 30°. Also, find the area of the corresponding major sector (Use π= 3.14). Given Radius = r = 4 cm, θ=30° Now, Area of sector = 𝜽/𝟑𝟔𝟎 × 𝝅𝒓𝟐 = 30/360 × 3.14 × (4)2 = 𝟏/𝟏𝟐 × 𝟑.𝟏𝟒 × 𝟒 × 𝟒 = 1/3 × 3.14 × 4 = 12.56/3 cm2 = 4.19 cm2 Now, Area of major sector = Area of circle – Area of minor sector Area of circle = 𝜋𝑟2 = 3.14 × 42 = 3.14 × 16 = 50.24 cm2 Now, Area of major sector = Area of circle – Area of minor sector = 50.24 – 4.19 = 46.05 cm2

  1. Chapter 11 Class 10 Areas related to Circles
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo