1. Chapter 11 Class 9 Surface Areas and Volumes
  2. Serial order wise
  3. Ex 11.2
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Ex 11.2, 2 (iii) - Chapter 11 Class 9 Surface Areas and Volumes

Last updated at Dec. 16, 2024 by Teachoo

 

Transcript

Ex 11.2, 2 Assume = 22/7, unless stated otherwise. Find the surface area of a sphere of diameter: (iii) 3.5 cm Radius of sphere = r = /2 r = (3.5/2) cm = 1.75 cm Surface area of sphere = 4 r2 = (4 22/7 1.75 1.75)cm2 = 38.5 cm2
  1. Chapter 11 Class 9 Surface Areas and Volumes
  2. Serial order wise

    3. Ex 11.2

    Ex 11.3 →
Ex 11.3 →
Chapter 11 Class 9 Surface Areas and Volumes
Serial order wise

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo