1. Chapter 9 Class 8 Mensuration
  2. Serial order wise
  3. Ex 9.3
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Ex 9.3, 5 - Chapter 9 Class 8 Mensuration

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Ex 9.3, 5 Find the height of the cylinder whose volume is 1.54 ๐‘š^3and diameter of the base is 140 cm ?Given, Volume of cylinder = 1.54 ๐’Ž^๐Ÿ‘ & Diameter = 140 cm Radius = r = 140/2 cm = 70 cm = 70/100 m = ๐Ÿ•/๐Ÿ๐ŸŽ m We need to find height of the cylinder Let h be the height of the cylinder. Now, Volume of cylinder = ๐œ‹๐‘Ÿ^2 โ„Ž 1.54 = ๐…๐’“^๐Ÿ ๐’‰ ๐œ‹๐‘Ÿ^2 โ„Ž = 1.54 22/7ร—(7/10)^2ร— โ„Ž = 1.54 ๐Ÿ๐Ÿ/๐Ÿ•ร—๐Ÿ•/๐Ÿ๐ŸŽร—๐Ÿ•/๐Ÿ๐ŸŽ ร— ๐’‰ = ๐Ÿ๐Ÿ“๐Ÿ’/๐Ÿ๐ŸŽ๐ŸŽ (22 ร— 7)/100 โ„Ž = 154/100 (154 โ„Ž)/100 = 154/100 154 โ„Ž = 154 โ„Ž = 154/154 โ„Ž = 1 โˆด Height of cylinder = 1 m
  1. Chapter 9 Class 8 Mensuration
  2. Serial order wise

    3. Ex 9.3

    Examples →
Examples →
Chapter 9 Class 8 Mensuration
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo