Check sibling questions

In a regular polygon

  • All sides are equal
  • All angles are equal
  •  

Let

∠ A = ∠ B = ∠ C = ∠ D = ∠ E = ∠ F = x

 

We know that

  Sum of angles of a regular hexagon = (n – 2)  × 180°

      Putting n = 6

                 = (6 – 2) × 180°

              = 4 × 180°

            = 720°

 

Now,

  Sum of angles of a regular hexagon= 720°

  ∠ A + ∠ B + ∠ C + ∠ D + ∠ E + ∠ F = 720°

  x + x + x + x + x + x = 720°

  6x = 720°

  x = (720°)/6

  x = 120°

Thus,

  Interior Angle of a Regular Hexagon = 120°

In general

  Interior Angle of a Polygon × Number of sides = Sum of angles

  Interior Angle of a Regular Polygon  × n = (n – 2) × 180°

  Interior Angle of a Regular Polygon  = ((n - 2))/n   × 180°

 

 

  1. Chapter 3 Class 8 Understanding Quadrilaterals
  2. Concept wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo