Ex 4.1, 3 (i) - Chapter 4 Class 7 Simple Equations
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 4.1, 3 Solve the following equations by trial and error method: (i) 5p + 2 = 17 Putting p = 0 5p + 2 = 17 5(0) + 2 = 17 0 + 2 = 17 2 = 17 It is not true. ∴ p = 0 is not a solution. Putting p = 1 5p + 2 = 17 5(1) + 2 = 17 5 + 2 = 17 7 = 17 It is not true. ∴ p = 1 is not a solution. Putting p = 2 5p + 2 = 17 5(2) + 2 = 17 10 + 2 = 17 12 = 17 It is not true. ∴ p = 1 is not a solution. Putting p = 3 5p + 2 = 17 5(3) + 2 = 17 15 + 2 = 17 17 = 17 It is true. ∴ p = 3 is a solution
Ex 4.1
Ex 4.1, 2 Important
Ex 4.1, 3 (i) You are here
Ex 4.1, 3 (ii) Important
Ex 4.1, 4 (i)
Ex 4.1, 4 (ii) Important
Ex 4.1, 4 (iii)
Ex 4.1, 4 (iv) Important
Ex 4.1, 4 (v)
Ex 4.1, 4 (vi) Important
Ex 4.1, 4 (vii)
Ex 4.1, 4 (viii) Important
Ex 4.1, 4 (ix) Important
Ex 4.1, 5 (i)
Ex 4.1, 5 (ii) Important
Ex 4.1, 5 (iii) Important
Ex 4.1, 5 (iv)
Ex 4.1, 5 (v) Important
Ex 4.1, 5 (vi)
Ex 4.1, 5 (vii) Important
Ex 4.1, 5 (viii) Important
Ex 4.1, 6 (i)
Ex 4.1, 6 (ii) Important
Ex 4.1, 6 (iii)
Ex 4.1, 6 (iv) Important
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo