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What will be the smallest 3-digit number which divides 2, 4, 6 and leaves remainder 0?

Last updated at Dec. 16, 2024 by Teachoo

Smallest Number which divides 2, 4, 6 and leaves remainder 0

= LCM of 2, 4, 6

= 12
 

We need to find the smallest 3-digit number which will divide 2, 4, 6

Smallest 3 digit number = 100

We divide 100 by 12

 

So remainder is 4

But we need to find a number where remainder is 0.

So, 108 is the smallest 3 digit number divisible by 2, 4, 6

 

Transcript

What will be the smallest 3-digit number which divides 2, 4, 6 and leaves remainder 0? Smallest Number which divides 2, 4, 6 and leaves remainder 0 = LCM of 2, 4, 6 = 12 We need to find the smallest 3-digit number which will divide 2, 4, 6 Smallest 3 digit number = 100 We divide 100 by 12 If we get 12 here, the remainder will be 0. To get 12 we add (12 − 4) to number. So remainder is 4 But we need to find a number where remainder is 0. ∴ Required number = 100 + (12 − 4) = 100 + 8 = 108 So, 108 is the smallest 3 digit number divisible by 2, 4, 6
  1. Chapter 3 Class 6 Playing with Numbers
  2. Concept wise

    3. Statement questions on LCM

    Statement questions on HCF →
Statement questions on HCF →
Chapter 3 Class 6 Playing with Numbers
Concept wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo