Ex 14.1, 5 (i) - Chapter 14 Class 11 Probability
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 14.1, 5 Three coins are tossed. Describe Two events which are mutually exclusive. Since 3 coins are tossed , possible outcomes are S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} Two events which are mutually exclusive Let A be the event getting only head A = {HHH} Let B be the event getting only tail B = {TTT} So, A ∩ B = 𝜙 Since no element is common in A & B Hence A & B are mutually exclusive
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