1. Chapter 14 Class 10 Probability
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Example 6 - Chapter 14 Class 10 Probability

Last updated at Dec. 13, 2024 by Teachoo

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Example 6 Savita and Hamida are friends. What is the probability that both will have different birthdays? (ignoring a leap year). P(both have different birthday) = P(both will not have same birthday) = 1 โ€“ P(both will have same birthday) = 1 โ€“ 1/365 = (365 โˆ’ 1)/365 = ๐Ÿ‘๐Ÿ”๐Ÿ’/๐Ÿ‘๐Ÿ”๐Ÿ“ Example 6 Savita and Hamida are friends. What is the probability that both will have (ii) same birthday? (ignoring a leap year). Number of days in an year = 365 Number of days when same birthday is possible = 1 P(both have same birthday) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘‘๐‘Ž๐‘ฆ๐‘  ๐‘คโ„Ž๐‘’๐‘Ÿ๐‘’ ๐‘กโ„Ž๐‘’๐‘ฆ ๐‘๐‘Ž๐‘› โ„Ž๐‘Ž๐‘ฃ๐‘’ ๐‘ ๐‘Ž๐‘š๐‘’ ๐‘๐‘–๐‘Ÿ๐‘กโ„Ž๐‘‘๐‘Ž๐‘ฆ ๐‘–๐‘› ๐‘Ž๐‘› ๐‘ฆ๐‘’๐‘Ž๐‘Ÿ)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘‘๐‘Ž๐‘ฆ๐‘  ๐‘–๐‘› ๐‘Ž๐‘› ๐‘ฆ๐‘’๐‘Ž๐‘Ÿ) = ๐Ÿ/๐Ÿ‘๐Ÿ”๐Ÿ“
  1. Chapter 14 Class 10 Probability
  2. Serial order wise

    3. Examples

    Case Based Questions (MCQ) →
Case Based Questions (MCQ) →
Chapter 14 Class 10 Probability
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo