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Question 5 - Past Year - 3 Mark Questions - Chapter 12 Class 10 - Electricity

Last updated at Dec. 13, 2024 by Teachoo

Consider the following circuit:

What would be the readings of the ammeter and the voltmeter when key is closed? Give reason to justify your answer.

 

Answer:

Total resistance, R = R 1 + R 2 + R 3

      = 5 + 8 + 12 

      = 25 ohm

V = 6 volts

According to ohm’s law,

V = IR

I = V / R 

  = 6 / 25 

  = 0.24 A

Current through 12 ohm resistor = 0.24 A

Voltage = I * R 

               = 0.24 * 12

                = 2.88 V

Therefore,

  • Ammeter reading = 0.24 A
  • Voltmeter reading = 2.88 V
  1. Class 10
  2. Chapter 12 Class 10 - Electricity

    3. Past Year - 3 Mark Questions

    Past Year - 5 Mark Questions →
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Class 10
Chapter 12 Class 10 - Electricity

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Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 14 years and a teacher from the past 18 years. He teaches Science, Economics, Accounting and English at Teachoo