1. Chapter 2 Class 10 Polynomials
  2. Serial order wise
  3. Examples
Check sibling questions

Question 1 - Examples - Chapter 2 Class 10 Polynomials

Last updated at Dec. 13, 2024 by Teachoo

Transcript

Question 1 Divide 2x2 + 3x + 1 by x + 2 We follow these steps 1. Since it is 2x2, we multiply x by 2x 2. So, our remainder will be difference of 2x2 + 3x and 2x2 + 4x 3. Which comes out to be -x 4. So, we muliply by -1 5. The remainder will be the difference of -x + 1 and -x -2. 5. Which comes out to be +3 Thus, Quotient = 2x – 1 Remainder = 3
  1. Chapter 2 Class 10 Polynomials
  2. Serial order wise

    3. Examples

    Case Based Questions (MCQ) →
Case Based Questions (MCQ) →
Chapter 2 Class 10 Polynomials
Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo