1. Chapter 2 Class 6 Whole Numbers
  2. Serial order wise
  3. Sum, Multiplication, Division of Whole Numbers
Check sibling questions

Question 2 (f) - Sum, Multiplication, Division of Whole Numbers - Chapter 2 Class 6 Whole Numbers

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Question 2 Find the product by suitable rearrangement: (f) 125 × 40 × 8 × 25 125 × 40 × 8 × 25 = (125 × 8) x (40 × 25) = (125 × 8) x (4 × 10 × 25) = (125 × 8) x (4 × 25 × 10) = 1000 × (100 × 10) = 1000 × 1000 = 1000000 Note: 25 × 4 = 100 ends with 0 and 125 × 8 = 1000 also ends with 0 So, we multiply them
  1. Chapter 2 Class 6 Whole Numbers
  2. Serial order wise

    3. Sum, Multiplication, Division of Whole Numbers

    Properties of Whole Numbers →
Properties of Whole Numbers →
Chapter 2 Class 6 Whole Numbers
Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo