Example 5 (ii) - Chapter 4 Class 7 Simple Equations
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Example 5 Solve: (b) 2p – 1 = 23 2p − 1 = 23 Adding 1 to both sides. 2p − 1 + 1 = 23 + 1 2p = 24 Dividing 2 both sides 2𝑝/2 = 24/2 p = 12
Examples
Example 1 (ii) Important
Example 1 (iii) Important
Example 1 (iv)
Example 2 (i) Important
Example 2 (ii)
Example 2 (iii)
Example 2 (iv) Important
Example 3
Example 4 Important
Example 5 (i)
Example 5 (ii) Important You are here
Example 6
Example 7 (a)
Example 7 (b) Important
Example 8
Example 9 Important
Example 10 Important
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo