1. Chapter 11 Class 9 Surface Areas and Volumes
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  3. Ex 11.1
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Ex 11.1, 2 - Chapter 11 Class 9 Surface Areas and Volumes

Last updated at Dec. 13, 2024 by Teachoo

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Ex 11.1, 2 Find the total surface area of a cone, if its slant height is 21 m and diameter of its base is 24 m. [๐ด๐‘ ๐‘ ๐‘ข๐‘š๐‘’ ๐œ‹=22/7] Total surface area of cone = ฯ€r(r + l) Radius (r) of the base of cone = (24/2) m = 12 m Slant height (l) of cone = 21 m Total surface area of cone = ฯ€r(r + l) = [22/7ร—12ร—(12+21)] m2 = (22/7ร—12ร—33) m2 = 1244.57 m2
  1. Chapter 11 Class 9 Surface Areas and Volumes
  2. Serial order wise

    3. Ex 11.1

    Ex 11.2 →
Ex 11.2 →
Chapter 11 Class 9 Surface Areas and Volumes
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo