1. Chapter 11 Class 9 Surface Areas and Volumes
  2. Serial order wise
  3. Ex 11.1
Check sibling questions

Ex 11.1, 1 - Chapter 11 Class 9 Surface Areas and Volumes

Last updated at Feb. 13, 2025 by Teachoo

 

Transcript

Ex 11.1, 1 Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area. [๐ด๐‘ ๐‘ ๐‘ข๐‘š๐‘’ ๐œ‹=22/7] Curved Surface Area of cone of cone = ฯ€rl Radius (r) of the base of cone = (10.5/2) cm = 5.25 cm Slant height (l) of cone = 10 cm Curved Surface Area of cone of cone = ฯ€rl = (22/7ร—5.25ร—10) cm2 = (22/7ร—525/100ร—10) cm2 = ("22" ร—75/100ร—10) cm2 = 165 m2 Therefore, the curved surface area of the cone is 165 cm2.
  1. Chapter 11 Class 9 Surface Areas and Volumes
  2. Serial order wise

    3. Ex 11.1

    Ex 11.2 →
Ex 11.2 →
Chapter 11 Class 9 Surface Areas and Volumes
Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo