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Example 3.1 - Chapter 3 Class 9 - Atoms And Molecules

Last updated at Dec. 16, 2024 by Teachoo

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Example 3.1 (a) Calculate the relative molecular mass of water (H2O). Atomic mass of Hydrogen = 1 u Atomic mass of Oxygen = 16 u Relative molecular mass of water (H2O) = 2 × Atomic Mass of Hydrogen + 1 × Atomic Mass of Oxygen = 2 × 1 + 1 × 16 = 18 u Example 3.1 (b) Calculate the molecular mass of HNO3 Atomic mass of Hydrogen = 1 u Atomic mass of Nitrogen = 14 u Atomic mass of Oxygen = 16 u Relative molecular mass of HNO3 = Atomic Mass of Hydrogen + Atomic Mass of Nitrogen + 3 × Atomic Mass of Oxygen = 1 + 14 + 3 × 16 = 1 + 14 + 48 = 63 u
  1. Class 9
  2. Chapter 3 Class 9 - Atoms And Molecules

    3. Examples from NCERT Book

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Class 9
Chapter 3 Class 9 - Atoms And Molecules

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Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 14 years and a teacher from the past 18 years. He teaches Science, Economics, Accounting and English at Teachoo