Last updated at Dec. 13, 2024 by Teachoo
Ex 6.1, 5 In the given figure, POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR. Prove that ∠ROS = 1/2 (∠QOS – ∠POS ) Since OR ⊥ PQ Hence, ∠ ROP = 90° & ∠ ROQ = 90° We can say that ∠ ROP = ∠ ROQ ∠ POS + ∠ ROS = ∠ ROQ ∠ POS + ∠ ROS = ∠ QOS – ∠ ROS ∠ SOR + ∠ ROS = ∠ QOS – ∠ POS 2(∠ ROS) = ∠ QOS – ∠ POS ∠ ROS = 1/2 ("∠ QOS – ∠ POS" ) ∠ ROS = 1/2 ("∠ QOS – ∠ POS" ) Hence proved
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo