Example 3 - Chapter 4 Class 9 Linear Equations in Two Variables
Last updated at Dec. 13, 2024 by Teachoo
Last updated at Dec. 13, 2024 by Teachoo
Example 3 Find four different solutions of the equation x + 2y = 6. For x = 0, 0 + 2y = 6 2y = 6 y = 6/2 = 3 So, (0, 3) is also a solution For y = 0, x + 2(0) = 6 x + 0 = 6 x = 6 So, "(6, 0)" is a solution For x = 1, (1) + 2y = 6 1 + 2y = 6 2y = 6 – 1 2y = 5 y = 5/2 So, (1, 5/2) is also a solution For y = 1 x + 2(1) = 6 x + 2 = 6 x = 6 – 2 x = 4 So, (4, 1) is also a solution So four solutions of the given equation are: (0, 3), (6, 0) , (1, 5/2) and (4, 1).
Examples
Example 1 (ii)
Example 1 (iii) Important
Example 1 (iv)
Example 2 (i)
Example 2 (ii)
Example 2 (iii) Important
Example 2 (iv)
Example 3 You are here
Example 4 (i)
Example 4 (ii) Important
Example 4 (iii)
Question 1 Important
Question 2
Question 3 Important
Question 4
Question 5 Important
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo