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Ex 6.5, 6 Angles Q and R of a ∆PQR are 25° and 65º. Write which of the following is true: (i) PQ2 + QR2 = RP2 (ii) PQ2 + RP2 = QR2 (iii) RP2 + QR2 = PQ2 In ∆PQR, ∠Q = 25°, ∠R = 65°, ∠P = ? By Angle Sum Property, ∠P + ∠Q + ∠R = 180° ∠P + 25° + 65° = 180° ∠P + 95° = 180° ∠P = 180° − 90° ∠P = 90° ∴ ∆PQR is a right angled triangle. By Pythagoras Theorem, i.e. 〖𝑃𝑄〗^2 = 〖𝑅𝑃〗^2 + 〖𝑄𝑅〗^2 Hence (ii) is true

  1. Chapter 6 Class 7 Triangle and its Properties
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo